Regarding IV flow rates

by Jim
(Toledo, Ohio)

A Microdrip IV has been set to drop 10 gtt/min. The bag contains 450mg of a particular drug in a total of 1000ml. How many mg of the drug will the patient receive per hour if the set is calibrated to deliver 60 gtt/mL?
A. 4.5mg
B. 270mg
C. 2.7grams
D. None of the above

Please include the equation?

Thank you!
Jim

____________________________________


Reply (By Keith)
Jim, I'm answering this on my phone from a Starbucks hot-spot, so I didn't write it down. Hope it's correct. Here's what I think:



600 drops in 1/Hour
----------------------------
60 drops per/mL

= 10mL/Hour

450mg - - - 4.5mg
------- = --------
1000ml - - - 10ml



Someone else, please hit comment below and show the work on this one. Thanks.

Comments for
Regarding IV flow rates

Click here to add your own comments

Apr 12, 2011
How I did this problem...
by: Rob

We know that:

10gtt
-----
1 min.

So, lets figure out how many drops are in 60 minutes.

10gtt - X gtt
----- = -----
1 min.- 60 min

X = 600gtt (in 60 minutes)

We also know that:

60gtt
-----
1 mL

So, lets figure out how many mL are in 600gtt

60gtt - 600gt
----- = -----
1 mL - X mL

X = 10mL for every 600gtt

You then know that:

450mg
-----
1000mL

So just plug in 10mL to find out how many mg it will be

450mg - X mg
----- = -----
1000mL- 10mL

X = 4.5mg will be transferred to the patient-per hour.

Apr 10, 2011
Willing to try it...
by: Anonymous

If this is wrong, please correct me! Thanks :).

There are 450mg/1000mL, therefor 0.45mg/per mL in the bag of solution.

Then we have calibration of 60gtts/mL, and it is set to drop 10gtts/min.

So that tells me that I can get 60 gtts/6 minutes.

And 60 gtts is equal to 1 ml, as stated in the calibration. 1 ml is also equal to 0.45mg in the solution bag. So...if...

60gtts = 1mL = 0.45mg Then,

0.45mg / 6 minutes = ? mg / 60 minutes

Solve for the ? and I get 4.5 mg.

Am I right?

Apr 09, 2011
Regarding IV flow Rates
by: Jim

Thank you Keith. Nowhere in my Pharm Tech study book is this problem covered.

Click here to add your own comments

Join in and write your own page! It's easy to do. How?
Simply click here to return to Ask a Math Question






privacy
{ezoic-ad-1}
 
 
{ez_footer_ads}