Share

Additional Info

alligation practice question

by Donna
(Murrieta Ca. US)

Doctors order: 50 ml of a 12% boric solution. The pharmacy carries only 80% boric solution. How much concentrate will you need? How much dileunt?

Comments for
alligation practice question

Click here to add your own comments

Mar 18, 2012
Tic tac toe
by: Anonymous

Using tic tac toe (alligation)

find the difference diagonally.

80% 12 - 12/80 times 50mL= 7.5 mL of 80%
12
00% 68 - 68/80 times 50mL = 42.5 mL of 0%

Nov 04, 2011
hope this will not confuse you more
by: Anonymous

using this formula CIVI=C2V2

(.12)(50)=(.80)(X)
1.2X50/.8 = 7.5 -50= 42.5

ANSWER 7.5 AND 42.5

Nov 04, 2011
answer using algebra equation
by: Anonymous

c1v1=c2v2
{.12}{50}=(.80)(x)
x=.75mg of 80%

Nov 02, 2011
Diluent
by: Anonymous

The diluent is the subtraction of the concentration found 7.50mL from the volume = 50 mL

Oct 05, 2011
alligation practice question
by: Anonymous

where did the 42.5ml come from?

Sep 06, 2011
Simple Solution
by: ChRxis

D
--- x Q
H

Using this formula, you can easily figure out the amount of each ingredient.

D = stg you desire, H = stg you have, Q = qty

12
---- x 50
80

7.5ml of the 80%, then the remainder would be diluent...42.5ml

You can also use an alligation to solve this problem, although you will automatically get the equation above in the upper right hand corner of your alligation. So why not just use what we did first?

Jul 15, 2011
It is correct
by: Anonymous

7.5ml of 80% and 42.5ml of diluent are right!

Jul 12, 2011
A little confused
by: Anonymous

I got 7.5 ml of 80% concentrate, and 42.5ml of dilution. Someone got the same as me. is it right or what. Help.

Jun 06, 2011
I got...
by: Tait

I got 7.5 ml of 80 % concentrate, and 42.5 ml of dilution.

May 30, 2011
ANSWER TO LAST MATH
by: BONNIE

50 AT 12 PERCENT 80 PERCENT SOULTION ANSWER IS 80 TIMES 12 = 96 BUT WOULD BE EITHER 9.6 0R ROUND TO 1OO

Click here to add your own comments

Join in and write your own page! It's easy to do. How?
Simply click here to return to Ask a Math Question






privacy